College physics 9Th Edition By Alan Giambattista - Test Bank

College physics 9Th Edition By Alan Giambattista - Test Bank   Instant Download - Complete Test Bank With Answers     Sample Questions Are Posted Below   College Physics, 9e (Giambattista) Chapter 5   Circular Motion   1) An object is moving in a circular path with a radius of 4.0 m. If the object moves …

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College physics 9Th Edition By Alan Giambattista – Test Bank

 

Instant Download – Complete Test Bank With Answers

 

 

Sample Questions Are Posted Below

 

College Physics, 9e (Giambattista)

Chapter 5   Circular Motion

 

1) An object is moving in a circular path with a radius of 4.0 m. If the object moves through an angle of 45 degrees, then the angle in radians is

  1. A) 0.25 radians.
  2. B) 0.53 radians.
  3. C) 0.79 radians.
  4. D) 1.02 radians.
  5. E) 1.44 radians.

 

Answer:  C

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

 

2) An object is moving in a circular path with a radius of 5.00 m. If the object moves through an angle of 270 degrees, then the tangential distance traveled by the object is

  1. A) 4.71 m.
  2. B) 15.2 m.
  3. C) 23.6 m.
  4. D) 40.2 m.

 

Answer:  C

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

 

3) An object is moving in a circular path of radius R. If the object moves through an angle of 30 degrees, then the angle in radians is

  1. A) 0.22 radians.
  2. B) 0.52 radians.
  3. C) 0.75 radians.
  4. D) 1.30 radians.
  5. E) 1.75 radians.

 

Answer:  B

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

 

 

4) An object is moving in a circular path of radius 4.00 m. If the object moves through an angle of 30.0 degrees, then the tangential distance traveled by the object is

  1. A) 3.66 m.
  2. B) 3.21 m.
  3. C) 2.84 m.
  4. D) 2.09 m.
  5. E) 1.75 m.

 

Answer:  D

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

 

5) An object is moving in a circular path of radius 4.00 m. If the object moves through an angle of 1.2 radians, then the tangential distance traveled by the object is

  1. A) 2.8 m.
  2. B) 3.2 m.
  3. C) 3.8 m.
  4. D) 4.3 m.
  5. E) 4.8 m.

 

Answer:  E

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

 

6) An object is moving in a circular path of radius 4.00 m. If the object moves through a tangential distance of 3.00 meters, then the angle the object travels through is

  1. A) 0.750 radians.
  2. B) 1.05 radians.
  3. C) 1.46 radians.
  4. D) 1.75 radians.
  5. E) 1.90 radians.

 

Answer:  A

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

 

 

7) A CD has a diameter of 12.0 cm. If the CD is rotating at a constant angular speed of 20.0 radians per second, then the period of the rotational motion is

  1. A) 0.143 s.
  2. B) 0.224 s.
  3. C) 0.314 s.
  4. D) 0.421 s.
  5. E) 0.558 s.

 

Answer:  C

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Period and Frequency

 

8) A CD has a diameter of 12.0 cm. If the CD is rotating at a constant angular speed of 20.0 radians per second, then the frequency of the rotational motion is

  1. A) 2.14 Hz.
  2. B) 3.18 Hz.
  3. C) 3.83 Hz
  4. D) 4.50 Hz.
  5. E) 4.89 Hz.

 

Answer:  B

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Period and Frequency

 

9) A CD has a diameter of 12.0 cm. If the CD is rotating at a constant frequency of 3.18 Hz, then the period of the rotational motion is

  1. A) 0.314 s.
  2. B) 0.441 s.
  3. C) 0.582 s.
  4. D) 0.698 s.
  5. E) 0.750 s.

 

Answer:  A

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Period and Frequency

 

 

10) A CD has a diameter of 12.0 cm. If the CD is rotating with a constant period of 0.314 seconds, then the frequency of the rotational motion is

  1. A) 4.00 Hz.
  2. B) 3.67 Hz.
  3. C) 3.18 Hz.
  4. D) 2.83 Hz.
  5. E) 2.15 Hz.

 

Answer:  C

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Period and Frequency

 

11) An object moving in a circle at a constant speed is

  1. A) accelerating in the direction of motion.
  2. B) accelerating toward the center of the circle.
  3. C) accelerating away from the center of the circle.
  4. D) not accelerating because its speed is constant.

 

Answer:  B

Type: MC

Topic:  Radial Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

 

12) A CD has a diameter of 12.0 cm. If the CD is rotating at a constant angular speed of 200 revolutions per minute, then the linear speed of a point on the circumference is

  1. A) 1.06 m/s.
  2. B) 1.26 m/s.
  3. C) 1.39 m/s.
  4. D) 1.62 m/s.
  5. E) 1.32 m/s.

 

Answer:  B

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Relation Between Linear and Angular Speed

 

 

13) A CD has a diameter of 12.0 cm. If the CD is rotating at a constant angular speed of 20 radians per second, then the linear speed of a point on the circumference is

  1. A) 2.0 m/s.
  2. B) 1.9 m/s.
  3. C) 1.5 m/s.
  4. D) 1.2 m/s.
  5. E) 1.0 m/s.

 

Answer:  D

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Relation Between Linear and Angular Speed

 

14) A CD has a diameter of 12.0 cm. If the CD is rotating at a constant frequency of 4.00 rotations per second, then the period of the rotational motion is

  1. A) 0.250 s.
  2. B) 0.500 s.
  3. C) 0.750 s.
  4. D) 1.00 s.
  5. E) 1.25 s.

 

Answer:  A

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Period and Frequency

 

15) A CD has a diameter of 12.0 cm. If the CD is rotating at a constant frequency of 4.00 rotations per second, then the linear speed of a point on the circumference is

  1. A) 1.25 m/s.
  2. B) 1.31 m/s.
  3. C) 1.51 m/s.
  4. D) 1.82 m/s.
  5. E) 2.00 m/s.

 

Answer:  C

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Relation Between Linear and Angular Speed

 

 

16) A CD has a diameter of 12.0 cm. If the CD is rotating at a constant frequency of 6.00 rotations per second, then the angular speed is

  1. A) 21.5 rad/s.
  2. B) 26.9 rad/s.
  3. C) 29.6 rad/s.
  4. D) 33.3 rad/s.
  5. E) 37.7 rad/s.

 

Answer:  E

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Relation Between Linear and Angular Speed

 

17) A CD has a diameter of 12.0 cm. If the CD is rotating at a constant angular velocity of 25 radians per second, then the linear speed of a point on the circumference is

  1. A) 1.0 m/s.
  2. B) 1.5 m/s.
  3. C) 2.0 m/s.
  4. D) 2.5 m/s.
  5. E) 3.0 m/s.

 

Answer:  B

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Relation Between Linear and Angular Speed

 

18) A 4.00 kg mass is moving in a circular path of radius 2.50 m with a constant angular speed of 5.00 rad/sec. The magnitude of the radial force on the mass is

  1. A) 250 N.
  2. B) 185 N.
  3. C) 153 N.
  4. D) 107 N.
  5. E) 94.0 N.

 

Answer:  A

Type: MC

Topic:  Radial Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Applying Newton’s Second Law to Uniform Circular Motion

 

 

19) A 4.0 kg mass is moving in a circular path of radius 2.5 m with a constant linear speed of 5.0 m/s. The magnitude of the radial force on the mass is

  1. A) 20 N.
  2. B) 25 N.
  3. C) 35 N.
  4. D) 40 N.
  5. E) 45 N.

 

Answer:  D

Type: MC

Topic:  Radial Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Applying Newton’s Second Law to Uniform Circular Motion

 

20) A 4.00 kg mass is moving in a circular path with a constant angular speed of 5.00 rad/sec and with a linear speed of 5.00 m/sec. The magnitude of the radial force on the mass is

  1. A) 90.0 N.
  2. B) 100 N.
  3. C) 125 N.
  4. D) 169 N.
  5. E) 200 N.

 

Answer:  B

Type: MC

Topic:  Radial Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Applying Newton’s Second Law to Uniform Circular Motion

 

21) A 4.00 kg mass is moving in a circular path of radius 4.10 m with a constant angular speed of 5.00 rad/sec. The radial force on the mass is

  1. A) 267 N toward the center.
  2. B) 294 N toward the center.
  3. C) 302 N toward the center.
  4. D) 350 N toward the center.
  5. E) 410 N toward the center.

 

Answer:  E

Type: MC

Topic:  Radial Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Applying Newton’s Second Law to Uniform Circular Motion

 

 

22) A 4.00 kg mass is moving in a circular path of radius 3.20 m with a constant linear speed of 6.20 m/s. The radial force on the mass is

  1. A) 40.2 N away from the center.
  2. B) 48.1 N toward the center.
  3. C) 50.5 N away from the center.
  4. D) 59.0 N toward the center.
  5. E) 62.3 N away from the center.

 

Answer:  B

Type: MC

Topic:  Radial Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Applying Newton’s Second Law to Uniform Circular Motion

 

23) A 2.60 kg mass is moving in a circular path with a constant angular speed of 5.50 rad/sec and with a linear speed of 3.50 m/s. The magnitude of the radial force on the mass is

  1. A) 30.4 N.
  2. B) 40.5 N.
  3. C) 50.1 N.
  4. D) 60.5 N.
  5. E) 66.7 N.

 

Answer:  C

Type: MC

Topic:  Radial Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Applying Newton’s Second Law to Uniform Circular Motion

 

24) A 0.500 kg stone is moving in a vertical circular path attached to a string that is 75.0 cm long. The stone is moving around the path at a constant frequency of 1.50 rev/sec. At the moment the stone is overhead, the stone is released. The speed of the stone when it leaves the circular path is

  1. A) 5.55 m/s.
  2. B) 7.07 m/s.
  3. C) 7.75 m/s.
  4. D) 8.35 m/s.
  5. E) 9.00 m/s.

 

Answer:  B

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Relation Between Linear and Angular Speed

 

25) A 0.500 kg stone is moving in a vertical circular path attached to a string that is 75.0 cm long. The stone is moving around the path at a constant frequency of 2.20 rev/sec. At the moment the stone is overhead, the stone is released. The velocity of the stone when it leaves the circular path is

  1. A) 10.4 m/s horizontal.
  2. B) 10.4 m/s vertical.
  3. C) 22.0 m/s horizontal.
  4. D) 22.0 m/s vertical.
  5. E) 31.4 m/s horizontal.

 

Answer:  A

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Relation Between Linear and Angular Speed

 

26) A conical pendulum is constructed by attaching a mass to a string 2.5 m in length. The mass set in motion in a horizontal circular path about the vertical axis. If the angular speed of the conical pendulum is a constant 2.8 rad/s, then the angle the string makes with the vertical axis is

  1. A) 48 degrees.
  2. B) 60 degrees.
  3. C) 71 degrees.
  4. D) 75 degrees.
  5. E) 80 degrees.

 

Answer:  B

Type: MC

Topic:  Radial Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Applying Newton’s Second Law to Uniform Circular Motion

 

 

27) A conical pendulum is constructed by attaching a mass to a string 2.00 m in length. The mass is set in motion in a horizontal circular path about the vertical axis. If the angle the string makes with the vertical axis is 45.0 degrees, then the angular speed of the conical pendulum is

  1. A) 4.00 rad/s.
  2. B) 3.55 rad/s.
  3. C) 3.04 rad/s.
  4. D) 2.63 rad/s.
  5. E) 2.01 rad/s.

 

Answer:  D

Type: MC

Topic:  Radial Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Applying Newton’s Second Law to Uniform Circular Motion

 

28) A 2000 kg car is traveling on curved, icy road. The road is banked at an angle of 12.0 degrees and has a radius of curvature of 500 m. The speed of the car necessary to travel on the icy road without sliding is

  1. A) 32.3 m/s.
  2. B) 40.5 m/s.
  3. C) 42.8 m/s.
  4. D) 49.5 m/s.
  5. E) 50.2 m/s.

 

Answer:  A

Type: MC

Topic:  Unbanked and Banked Curves

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Application of Radial Acceleration and Contact Forces

 

 

29) A 2000 kg car is traveling on a banked, curved, icy road. The speed of the car is 25.0 m/s and the road has a radius of curvature of 500 m. If the car is to travel on the icy road without sliding, then the angle of the banked road should be

  1. A) 25.7 degrees.
  2. B) 21.0 degrees.
  3. C) 12.7 degrees.
  4. D) 10.5 degrees.
  5. E) 7.27 degrees.

 

Answer:  E

Type: MC

Topic:  Unbanked and Banked Curves

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Application of Radial Acceleration and Contact Forces

 

30) A 2000 kg car is traveling on a curved, icy road without sliding. The speed of the car is 30 m/s and the road is banked at an angle of 20.0 degrees. The radius of curvature of the road is

  1. A) 175 m.
  2. B) 204 m.
  3. C) 252 m.
  4. D) 302 m.
  5. E) 375 m.

 

Answer:  C

Type: MC

Topic:  Unbanked and Banked Curves

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Application of Radial Acceleration and Contact Forces

 

 

31) An airplane is traveling at 150 m/s in level flight. In order to make a change in direction, the airplane travels in a horizontal curved path. To fly in the curved path, the pilot banks the airplane at an angle such that the lift has a horizontal component that provides the horizontal radial acceleration to move in a horizontal circular path. If the airplane is banked at an angle of 12.0 degrees, then the radius of curvature of the curved path of the airplane is

  1. A) 10.8 km.
  2. B) 8.74 km.
  3. C) 8.00 km.
  4. D) 7.33 km.
  5. E) 6.90 km.

 

Answer:  A

Type: MC

Topic:  Unbanked and Banked Curves

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Application of Radial Acceleration and Contact Forces

 

32) A 2000 kg car is traveling on a curved, icy road without sliding. The velocity of the car is 32.0 m/s and the road is banked at an angle of 20.0 degrees. The radius of curvature of the road is

  1. A) 125 m.
  2. B) 210 m.
  3. C) 287 m.
  4. D) 310 m.
  5. E) 350 m.

 

Answer:  C

Type: MC

Topic:  Unbanked and Banked Curves

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Application of Radial Acceleration and Contact Forces

 

 

33) An airplane is traveling at 250 m/s in level flight. In order to make a change in direction, the airplane travels in a horizontal curved path. To fly in the curved path, the pilot banks the airplane at an angle such that the lift has a horizontal component that provides the horizontal radial acceleration to move in a horizontal circular path. If the airplane is banked at an angle of 15.0 degrees, then the radius of curvature of the curved path of the airplane is

  1. A) 20.1 km.
  2. B) 23.8 km.
  3. C) 25.0 km.
  4. D) 27.5 km.
  5. E) 30.1 km.

 

Answer:  B

Type: MC

Topic:  Unbanked and Banked Curves

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Application of Radial Acceleration and Contact Forces

 

34) A 5,000 kg satellite is orbiting the Earth in a circular path. The height of the satellite above the surface of the Earth is 800 km. The speed of the satellite is (ME = 5.98 × 1024 kg, RE = 6.37 × 106 m, G = 6.67 × 10−11 N·m2/kg2)

  1. A) 7,460 m/s.
  2. B) 6,830 m/s.
  3. C) 6,430 m/s.
  4. D) 5,950 m/s.
  5. E) 5,350 m/s.

 

Answer:  A

Type: MC

Topic:  Circular Orbits of Satellites and Planets

Accessibility:  Keyboard Navigation

Chapter:  05

 

 

35) A 5,000 kg satellite is orbiting the Earth in a circular path. The height of the satellite above the surface of the Earth is 800 km. The time it takes for the satellite to travel around the Earth is (ME = 5.98 × 1024 kg, RE = 6.37 × 106 m, G = 6.67 × 10−11 N·m2/kg2)

  1. A) 0.750 hours.
  2. B) 0.950 hours.
  3. C) 1.25 hours.
  4. D) 1.68 hours.
  5. E) 2.01 hours.

 

Answer:  D

Type: MC

Topic:  Circular Orbits of Satellites and Planets

Accessibility:  Keyboard Navigation

Chapter:  05

 

36) A 5,000 kg satellite is orbiting the Earth in a circular path. The height of the satellite above the surface of the Earth is 800 km. The angular speed of the satellite as it orbits the Earth is (ME = 5.98 × 1024 kg, RE = 6.37 × 106 m, G = 6.67 × 10−11 N·m2/kg2)

  1. A) 9.50 × 10−4rad/s.
  2. B) 1.04 × 10−3rad/s.
  3. C) 1.44 × 10−3rad/s.
  4. D) 1.90 × 10−3rad/s.
  5. E) 2.20 × 10−3rad/s.

 

Answer:  B

Type: MC

Topic:  Circular Orbits of Satellites and Planets

Accessibility:  Keyboard Navigation

Chapter:  05

 

37) A 5,000 kg satellite is orbiting the Earth in a geostationary orbit. The height of the satellite above the surface of the Earth is (ME = 5.98 × 1024 kg, RE = 6.37 × 106 m, G = 6.67 × 10−11 N·m2/kg2)

  1. A) 8.29 × 107
  2. B) 6.35 × 107
  3. C) 3.59 × 107
  4. D) 2.95 × 107
  5. E) 1.40 × 107

 

Answer:  C

Type: MC

Topic:  Circular Orbits of Satellites and Planets

Accessibility:  Keyboard Navigation

Chapter:  05

 

38) Two moons orbit a planet in nearly circular orbits. Moon A has orbital radius r, and moon B has orbital radius 4r. Moon A takes 20 days to complete one orbit. How long does it take moon B to complete one orbit?

  1. A) 320 days
  2. B) 160 days
  3. C) 20 days
  4. D) 80 days

 

Answer:  B

Type: MC

Topic:  Circular Orbits of Satellites and Planets

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Kepler’s Laws of Planetary Motion

 

39) A 1.00 kg stone attached to a 1.00 m long string is traveling in a vertical circular path. What is the minimum linear speed needed at the top of the circle to keep the string from going slack?

  1. A) 5.63 m/s
  2. B) 5.31 m/s
  3. C) 5.00 m/s
  4. D) 4.50 m/s
  5. E) 3.13 m/s

 

Answer:  E

Type: MC

Topic:  Nonuniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

 

40) A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.0 rad/sec2 acquires an angular velocity of 5.0 rad/sec. The CD continues rotating at 5.0 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the linear speed of a point 4.0 cm from the center at the time 2.0 seconds from the start?

  1. A) 0.060 m/s
  2. B) 0.080 m/s
  3. C) 0.10 m/s
  4. D) 0.14 m/s
  5. E) 0.18 m/s

 

Answer:  B

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

41) A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.0 rad/sec2 acquires an angular velocity of 5.0 rad/sec. The CD continues rotating at 5.0 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the radial acceleration of a point 4.0 cm from the center at the time 2.0 seconds from the start?

  1. A) 0.37 m/s2
  2. B) 0.30 m/s2
  3. C) 0.28 m/s2
  4. D) 0.21 m/s2
  5. E) 0.16 m/s2

 

Answer:  E

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

42) A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.0 rad/sec2 acquires an angular velocity of 5.0 rad/sec. The CD continues rotating at 5.0 rad/sec for 15 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the angular distance traveled by a point 4.0 cm from the center, at the time 2.0 seconds from the start?

  1. A) 2.0 rad
  2. B) 4.0 rad
  3. C) 6.0 rad
  4. D) 8.0 rad
  5. E) 10.0 rad

 

Answer:  A

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

 

43) A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.0 rad/sec2 acquires an angular velocity of 5.0 rad/sec. The CD continues rotating at 5.0 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the radial acceleration of a point 4.0 cm from the center at the time 10.0 seconds from the start?

  1. A) 2.0 m/s2
  2. B) 1.8 m/s2
  3. C) 1.0 m/s2
  4. D) 0.9 m/s2
  5. E) 0.6 m/s2

 

Answer:  C

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

44) A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.00 rad/sec2 acquires an angular velocity of 5.00 rad/sec. The CD continues rotating at 5.00 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the angular distance traveled by a point 4.00 cm from the center, at the time 10.0 seconds from the start?

  1. A) 27.6 rad
  2. B) 37.5 rad
  3. C) 40.7 rad
  4. D) 48.2 rad
  5. E) 51.2 rad

 

Answer:  B

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

 

45) A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.0 rad/sec2 acquires an angular velocity of 5.0 rad/sec. The CD continues rotating at 5.0 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the linear speed of a point 4.0 cm from the center at the time 10.0 seconds from the start?

  1. A) 0.50 m/s
  2. B) 0.40 m/s
  3. C) 0.30 m/s
  4. D) 0.20 m/s
  5. E) 0.10 m/s

 

Answer:  D

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

46) A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.0 rad/sec2 acquires an angular velocity of 5.0 rad/sec. The CD continues rotating at 5.0 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the radial acceleration of a point 4.0 cm from the center at the time 25.0 seconds from the start?

  1. A) 0.47 m/s2
  2. B) 0.40 m/s2
  3. C) 0.34 m/s2
  4. D) 0.24 m/s2
  5. E) 0.20 m/s2

 

Answer:  C

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

 

47) A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.00 rad/sec2 acquires an angular velocity of 5.00 rad/sec. The CD continues rotating at 5.00 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the angular distance traveled by a point 4.00 cm from the center, at the time 25.0 seconds from the start?

  1. A) 107 rad
  2. B) 193 rad
  3. C) 205 rad
  4. D) 237 rad
  5. E) 274 rad

 

Answer:  A

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

48) A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.0 rad/sec2 acquires an angular velocity of 5.0 rad/sec. The CD continues rotating at 5.0 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the linear speed of a point 4.0 cm from the center at the time 25.0 seconds from the start?

  1. A) 0.10 m/s
  2. B) 0.017 m/s
  3. C) 0.083 m/s
  4. D) 0.00 m/s
  5. E) 0.12 m/s

 

Answer:  E

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

 

49) A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.0 rad/sec2 acquires an angular velocity of 5.0 rad/sec. The CD continues rotating at 5.0 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the radial acceleration of a point 4.0 cm from the center at the time 15.0 seconds from the start?

  1. A) 0.5 m/s2
  2. B) 1.0 m/s2
  3. C) 1.8 m/s2
  4. D) 2.0 m/s2
  5. E) 2.6 m/s2

 

Answer:  B

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

50) A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.00 rad/sec2 acquires an angular velocity of 5.00 rad/sec. The CD continues rotating at 5.00 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the magnitude of the (total) acceleration of a point 4.00 cm from the center at the time 2.00 seconds from the start?

  1. A) 0.450 m/s2
  2. B) 0.314 m/s2
  3. C) 0.215 m/s2
  4. D) 0.165 m/s2
  5. E) 0.100 m/s2

 

Answer:  D

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

 

51) A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.00 rad/sec2 acquires an angular velocity of 5.00 rad/sec. The CD continues rotating at 5.00 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the magnitude of the (total) acceleration of a point 4.00 cm from the center at the time 10.0 seconds from the start?

  1. A) 0.65 m/s2
  2. B) 1.00 m/s2
  3. C) 1.25 m/s2
  4. D) 1.37 m/s2
  5. E) 1.86 m/s2

 

Answer:  B

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

52) A CD with a diameter of 12.0 cm starts from rest and with a constant angular acceleration of 1.00 rad/sec2 acquires an angular velocity of 5.00 rad/sec. The CD continues rotating at 5.00 rad/sec for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the magnitude of the (total) acceleration of a point 4.00 cm from the center at the time 30.0 seconds from the start?

  1. A) 0.0650 m/s2
  2. B) 0.0522 m/s2
  3. C) 0.0444 m/s2
  4. D) 0.0324 m/s2
  5. E) 0.0243 m/s2

 

Answer:  D

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

 

53) A 2.00 kg mass is moving in a circular path with a radius of 5.00 cm. The mass starts from rest and, with constant angular acceleration, obtains an angular velocity of 6.00 rad/sec in 3.00 sec. The mass then comes to a stop with constant angular acceleration in 4.00 sec. The radial component of acceleration of the mass at 2.00 sec is

  1. A) 1.220 m/s2.
  2. B) 0.980 m/s2.
  3. C) 0.800 m/s2.
  4. D) 0.656 m/s2.
  5. E) 0.100 m/s2.

 

Answer:  C

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

54) A 2.0 kg mass is moving in a circular path with a radius of 5.00 cm. The mass starts from rest and, with constant angular acceleration, obtains an angular velocity of 6.00 rad/sec in 3.00 sec. The mass then comes to a stop with constant angular acceleration in 4.00 sec. The radial component of acceleration of the mass at 5.00 sec after the start is

  1. A) 2.50 m/s2.
  2. B) 2.03 m/s2.
  3. C) 1.25 m/s2.
  4. D) 0.980 m/s2.
  5. E) 0.450 m/s2.

 

Answer:  E

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

 

55) A CD has a diameter of 12.0 cm. If the CD starts from rest and has a constant angular acceleration of 2.0 rad/sec2, then the angular velocity of the CD after 3.0 sec is

  1. A) 12 rad/s.
  2. B) 10 rad/s.
  3. C) 9.0 rad/s.
  4. D) 8.0 rad/s.
  5. E) 6.0 rad/s.

 

Answer:  E

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

56) A CD has a diameter of 12.0 cm and is rotating at an angular velocity of 10.0 rad/sec. If the CD has a constant angular acceleration of −0.5 rad/sec2, then the angular velocity of the CD after 3.0 sec is

  1. A) 5.7 rad/s.
  2. B) 6.2 rad/s.
  3. C) 7.9 rad/s.
  4. D) 8.5 rad/s.
  5. E) 9.8 rad/s.

 

Answer:  D

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

57) A CD has a diameter of 12.0 cm. If the CD starts from rest and has a constant angular acceleration of 2.0 rad/sec2, then the linear speed of a point 3.0 cm from the center of the CD after 3.0 sec is

  1. A) 18 cm/s.
  2. B) 21 cm/s.
  3. C) 25 cm/s.
  4. D) 32 cm/s.
  5. E) 45 cm/s.

 

Answer:  A

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

58) A CD has a diameter of 12.0 cm. If the CD starts from rest and has a constant angular acceleration of 2.0 rad/sec2, then the tangential acceleration of a point 3.0 cm from the center of the CD after 3.0 sec is

  1. A) 0.40 m/s2.
  2. B) 0.25 m/s2.
  3. C) 0.10 m/s2.
  4. D) 0.06 m/s2.
  5. E) 0.03 m/s2.

 

Answer:  D

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

59) A CD has a diameter of 12.0 cm. If the CD starts from rest and has a constant angular acceleration of 2.00 rad/sec2, then the radial acceleration of a point 3.00 cm from the center of the CD after 3.00 sec is

  1. A) 0.950 m/s2.
  2. B) 1.08 m/s2.
  3. C) 1.25 m/s2.
  4. D) 1.58 m/s2.
  5. E) 1.83 m/s2.

 

Answer:  B

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

 

60) A CD has a diameter of 12.0 cm. If the CD starts from rest and has a constant angular acceleration of 0.600 rad/sec2, then the magnitude of the (total) acceleration of a point 3.00 cm from the center of the CD after 1.30 sec is

  1. A) 0.0256 m/s2.
  2. B) 0.0306 m/s2.
  3. C) 0.0415 m/s2.
  4. D) 0.0472 m/s2.
  5. E) 0.0502 m/s2.

 

Answer:  A

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

61) The radius of the Earth is r. A satellite of mass 100 kg is at a point which is a distance 3r above the Earth’s surface. What is the satellite’s weight?

  1. A) 6.3 N
  2. B) 110 N
  3. C) 61 N
  4. D) 38 N

 

Answer:  C

Type: MC

Topic:  Apparent Weight and Artificial Gravity

Accessibility:  Keyboard Navigation

Chapter:  05

 

62) A roller coaster has a vertical loop with radius 29.5 m. What is the minimum speed of the roller coaster car at the top of the loop if the passengers do not lose contact with the seats?

  1. A) 10.0 m/s
  2. B) 14.0 m/s
  3. C) 17.0 m/s
  4. D) 19.0 m/s

 

Answer:  C

Type: MC

Topic:  Nonuniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

 

 

63) When a girl swings in a tire swing, the tangential acceleration in the rope

  1. A) is the greatest at the highest point of the motion.
  2. B) is the greatest at the lowest point of the motion.
  3. C) is the greatest at a point neither highest nor lowest.
  4. D) is constant.

 

Answer:  A

Type: MC

Topic:  Nonuniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

 

64) A 35.0 kg child swings on a rope with a length of 6.50 m that is hanging from a tree. At the bottom of the swing the child is moving at a speed of 4.20 m/s. What is the tension in the rope?

  1. A) 95.0 N
  2. B) 438 N
  3. C) 343 N
  4. D) 366 N

 

Answer:  B

Type: MC

Topic:  Nonuniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

 

65) A 4,000 kg satellite is traveling in a circular orbit 200 km above the surface of the Earth. A 30.0 gram marble is dropped inside the satellite. What is the force of gravity on the marble as viewed by the observers on the Earth? (ME = 5.98 × 1024 kg, RE = 6.37 × 106 m, G = 6.67 × 10−11 N·m2/kg2)

  1. A) 0.405 N
  2. B) 0.362 N
  3. C) 0.277 N
  4. D) 0.202 N
  5. E) 0.185 N

 

Answer:  C

Type: MC

Topic:  Apparent Weight and Artificial Gravity

Accessibility:  Keyboard Navigation

Chapter:  05

 

 

66) A 4,000 kg satellite is traveling in a circular orbit 200 km above the surface of the Earth. A 30.0 gram marble is dropped inside the satellite. What is the magnitude of the acceleration of the marble as viewed by the observers inside the satellite? (ME = 5.98 × 1024 kg, RE = 6.37 × 106 m, G = 6.67 × 10−11 N·m2/kg2)

  1. A) 0.00 m/s2
  2. B) 1.62 m/s2
  3. C) 2.64 m/s2
  4. D) 4.90 m/s2
  5. E) 9.24 m/s2

 

Answer:  A

Type: MC

Topic:  Apparent Weight and Artificial Gravity

Accessibility:  Keyboard Navigation

Chapter:  05

 

67) A 4,000 kg satellite is traveling in a circular orbit 200 km above the surface of the Earth. A 30.0 gram marble is dropped inside the satellite. What is the magnitude of the acceleration of the marble as viewed by the observers on the Earth? (ME = 5.98 × 1024 kg, RE = 6.37 × 106 m, G = 6.67 × 10−11 N·m2/kg2)

  1. A) 9.80 m/s2
  2. B) 9.24 m/s2
  3. C) 8.90 m/s2
  4. D) 8.62 m/s2
  5. E) 7.95 m/s2

 

Answer:  B

Type: MC

Topic:  Apparent Weight and Artificial Gravity

Accessibility:  Keyboard Navigation

Chapter:  05

 

 

68) A boy on a bicycle rides in a circle of radius ro at speed vo. If the boy rides at the same radius ro, by what approximate factor must he change his speed in order to triple his radial acceleration?

  1. A) 3.0
  2. B) 0.58
  3. C) 0.33
  4. D) 1.7
  5. E) 0.11
  6. F) 9.0

 

Answer:  D

Type: MC

Topic:  Radial Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Magnitude of Radial Acceleration

 

69) A boy on a bicycle rides in a circle of radius ro at speed vo. If the boy now rides at a radius equal to half the initial radius ro, by what approximate factor must he change his speed in order to have the same radial acceleration?

  1. A) 0.25
  2. B) 2
  3. C) 0.71
  4. D) 4
  5. E) 1.4
  6. F) 0.5

 

Answer:  C

Type: MC

Topic:  Radial Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Magnitude of Radial Acceleration

 

 

70) The Crab Pulsar is a neutron star, rotating with a period of 33.085 ms. It is estimated to have an equatorial radius of 15 km, about average for a neutron star. What is the radial acceleration of an object on the surface at the equator of the pulsar?

  1. A) 5.4 x 108m/s2
  2. B) 2.7 x 108m/s2
  3. C) 8.9 x 108m/s2
  4. D) 6.7 x 108m/s2

 

Answer:  A

Type: MC

Topic:  Radial Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Magnitude of Radial Acceleration

 

71) A car travels at 17 m/s without skidding around a 35 m radius unbanked curve. What is the minimum value of the static friction coefficient between the tires and the road?

  1. A) 0.84
  2. B) 0.050
  3. C) 0.0014
  4. D) 0.024

 

Answer:  A

Type: MC

Topic:  Unbanked and Banked Curves

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Application of Radial Acceleration and Contact Forces

 

72) A car travels around a 35 m radius unbanked curve. The static friction coefficient between the tires and the road is 0.45. What is the maximum speed at which the car can travel without slipping around this curve?

  1. A) 2.8 m/s
  2. B) 27.6 m/s
  3. C) 12.4 m/s
  4. D) 7.5 m/s

 

Answer:  C

Type: MC

Topic:  Unbanked and Banked Curves

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Application of Radial Acceleration and Contact Forces

 

 

73) A car travels around an unbanked curve at 17 m/s. If the static friction coefficient between the tires and the road is 0.45, what is the minimum radius curve that the car can take at this speed without slipping?

  1. A) 65 m
  2. B) 3.9 m
  3. C) 15 m
  4. D) 8.1 m

 

Answer:  A

Type: MC

Topic:  Unbanked and Banked Curves

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Application of Radial Acceleration and Contact Forces

 

74) Two planets travel in circular orbits about a star at radii of ra = 2R and rb = R, respectively. What is the ratio of their periods Ta/Tb?

  1. A) 1.6
  2. B) 2.8
  3. C) 1.3
  4. D) 1.4
  5. E) 2.0

 

Answer:  B

Type: MC

Topic:  Circular Orbits of Satellites and Planets

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Kepler’s Laws of Planetary Motion

 

75) Two planets travel in circular orbits about a star. The period of planet A is T, while that of planet B is 3T. What is the ratio of their orbital radii, RA/RB?

  1. A) 0.33
  2. B) 0.19
  3. C) 0.48
  4. D) 0.69

 

Answer:  C

Type: MC

Topic:  Circular Orbits of Satellites and Planets

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Kepler’s Laws of Planetary Motion

 

 

76) A planet of mass M orbits a star in a circular orbit of radius R, with orbital period T. What would be the orbital period of another planet, orbiting at radius R, but having mass 2M?

  1. A) 0.71T
  2. B) T
  3. C) 1.4T
  4. D) 2T
  5. E) 0.50T

 

Answer:  B

Type: MC

Topic:  Circular Orbits of Satellites and Planets

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Kepler’s Laws of Planetary Motion

 

77) The Crab Pulsar is a neutron star, rotating with a period of about 33.085 ms. It is estimated to have an equatorial radius of 15 km, about average for a neutron star. The pulsar is slowing in its rotation so that it is expected to come to rest 9.5 × 1010 s in the future. Assuming it is slowing with a constant angular acceleration, what is the tangential acceleration of an object on the neutron star’s equator?

  1. A) 3.0 × 10−5m/s2
  2. B) 2.0 × 10−9m/s2
  3. C) 3.2 × 10−10m/s2
  4. D) 7.6 × 10−7m/s2
  5. E) 4.8 × 10−6m/s2

 

Answer:  A

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

 

78) The Crab Pulsar is a neutron star, rotating with a period of about 33.085 ms. It is estimated to have an equatorial radius of 15 km, about average for a neutron star. The pulsar is slowing in its rotation so that it is expected to come to rest 9.5 × 1010 s in the future. What is the magnitude of the average angular acceleration in this situation?

  1. A) 4.8 × 10−6rad/s2
  2. B) 3.0 × 10−5rad/s2
  3. C) 7.6 × 10−7rad/s2
  4. D) 2.0 × 10−9rad/s2
  5. E) 3.2 × 10−10rad/s2

 

Answer:  D

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

79) A figure skater spins at the end of her routine and slows down with an angular acceleration of 1.2 radians per second squared. If she initially spun with a period of 0.2 seconds, how many turns does she go through while slowing to a stop?

  1. A) 65
  2. B) 6
  3. C) 33
  4. D) 15

 

Answer:  A

Type: MC

Topic:  Angular Acceleration

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Constant Angular Acceleration

 

80) At what distance from the center of the Earth would one’s weight be half that recorded on the Earth’s surface? Let the Earth’s radius be R.

  1. A) 0.71R
  2. B) 2R
  3. C) 4R
  4. D) 1.4R

 

Answer:  D

Type: MC

Topic:  Apparent Weight and Artificial Gravity

Accessibility:  Keyboard Navigation

Chapter:  05

 

 

81) At what distance from the center of the Earth would one’s weight be one third of that recorded on the Earth’s surface? Let the Earth’s radius be R.

  1. A) 0.4R
  2. B) 1.7R
  3. C) 0.5R
  4. D) R
  5. E) 1.4R
  6. F) 3R

 

Answer:  B

Type: MC

Topic:  Apparent Weight and Artificial Gravity

Accessibility:  Keyboard Navigation

Chapter:  05

 

82) A circular space station (shaped like a big wheel) rotates 100 times in one hour. The apparent weight of an astronaut standing on the inside surface of the outer wall is equal to her weight on earth. How far from the axis of rotation is the inside surface of the station’s outer wall?

  1. A) 322 m
  2. B) 102 m
  3. C) 56 m
  4. D) 1012 m

 

Answer:  A

Type: MC

Topic:  Apparent Weight and Artificial Gravity

Accessibility:  Keyboard Navigation

Chapter:  05

 

83) A circular space station (shaped like a big wheel) rotates to produce “artificial gravity”. The apparent weight of an astronaut standing on the inside surface of the outer wall is equal to her weight on earth. The inside surface of the outer wall of the space station is 285 m from the axis of rotation. What is the period of rotation of the station?

  1. A) 92 s
  2. B) 34 s
  3. C) 213 s
  4. D) 183 s

 

Answer:  B

Type: MC

Topic:  Apparent Weight and Artificial Gravity

Accessibility:  Keyboard Navigation

Chapter:  05

 

 

84) An airplane flies in a vertical, semicircular arc in order to simulate “weightlessness” for its occupants. If the speed at which the plane flies is 750 km/hr, what is the radius of the semicircular path it flies in?

  1. A) 57 km
  2. B) 1.6 km
  3. C) 4.4 km
  4. D) 2.2 km
  5. E) 76 km

 

Answer:  C

Type: MC

Topic:  Apparent Weight and Artificial Gravity

Accessibility:  Keyboard Navigation

Chapter:  05

 

85) An airplane flies in a vertical, semicircular arc in order to simulate “weightlessness” for its occupants. If the radius of the semicircular path it flies is 3500 m, what is the speed at which the plane flies?

  1. A) 357 m/s
  2. B) 580 m/s
  3. C) 185 m/s
  4. D) 1180 m/s

 

Answer:  C

Type: MC

Topic:  Apparent Weight and Artificial Gravity

Accessibility:  Keyboard Navigation

Chapter:  05

 

86) A car travels on a road that, if viewed from the side, has a semicircular bump. When at the top of the bump, the occupants of the car feel as though they weigh half their normal weight. What is the speed of the car if the radius of the semicircle is 120 m?

  1. A) 107 m/s
  2. B) 53.7 m/s
  3. C) 34.3 m/s
  4. D) 24.2 m/s

 

Answer:  D

Type: MC

Topic:  Apparent Weight and Artificial Gravity

Accessibility:  Keyboard Navigation

Chapter:  05

 

 

87) A car travels on a road that, if viewed from the side, has a semicircular dip. When at the bottom of the dip, the occupants of the car feel as though they weigh twice their normal weight. What is the radius of the semicircle if the speed of the car is 27 m/s?

  1. A) 37 m
  2. B) 132 m
  3. C) 149 m
  4. D) 74 m

 

Answer:  D

Type: MC

Topic:  Apparent Weight and Artificial Gravity

Accessibility:  Keyboard Navigation

Chapter:  05

 

88) A ball rolls on the ground at a speed of 3.0 m/s without slipping. If the radius of the ball is 10 cm, what is the angular speed of the ball?

  1. A) 30 rad/s
  2. B) 0.30 rad/s
  3. C) 90 rad/s
  4. D) 3.3 rad/s

 

Answer:  A

Type: MC

Topic:  Description of Uniform Circular Motion

Accessibility:  Keyboard Navigation

Chapter:  05

Subtopic:  Rolling Without Slipping: Rotation and Translation Combined

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